Question

please solve the second sum
i am not getting​

Answer 1

Answer:

2y+3x=2xy

y=(2xy-3x)/2

5y+10x=35xy/6

now put the value of y in the above equation and solve you will get answers

Answer 2

✪ $\huge{\red{\underline{\overline{\mathbf{Question}}}}}$ ✪

→$4x+\frac{3}{y}=9\: ;\:3x+\frac{6}{y}=8$

✪ $\huge{\green{\underline{\overline{\mathbf{Answer}}}}}$ ✪

⇒Let $\frac{1}{y}$ be $z$

⇒$4x+3z=9\: ; \:3x+6z=8$

On Multiplying 1st equation with 2-

⇒$8x+6z=18$

Now subtracting 3x+6z=8 from This:-

.8x+$\cancel{6z}$=18

-3x-$\cancel{6z}$=-8

----------------

5x=10

----------------

⇒$x=\frac{10}{5}$

⇒$\Large{\blue{x=2}}$

Using this Value in 3x+6z=8

$3\times 3 +6z=8$

⇒$6z=-1$

⇒$z=\frac{-1}{6}$

Now-

$\frac{1}{y}=z$

⇒$y=-6$

⇒$\huge{\pink{\overbrace{\underbrace{x=2 \: \& \: y=-6}}}}$

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