please solve the third one
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fireboy:
kk
u blocked me
um... for me it says u blocked me
i am from kota
i can not understand what are want to say
which class
5th
this is 8th class
i can answer for you question
how,u told 5th class
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hope it will helps...
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this is based on volume expansion concept .
use formula ,
V = V° ( 1 + Y∆T)
let volume of vessel = V
at 0° C volume of liquid = v/6
at 200° C volume of liquid will be = v/5
so, V = v/5
V° = v/6
now,
v/5 = v/6{ 1+ Y(200-0)}
1/5 = 1/6 ( 1+ 200Y)
6/5 = 1+ 200Y
1.2 = 1 + 200Y
0.2 =200Y
Y=0.2/200 = 0.001 /°C
option (b) is correct
use formula ,
V = V° ( 1 + Y∆T)
let volume of vessel = V
at 0° C volume of liquid = v/6
at 200° C volume of liquid will be = v/5
so, V = v/5
V° = v/6
now,
v/5 = v/6{ 1+ Y(200-0)}
1/5 = 1/6 ( 1+ 200Y)
6/5 = 1+ 200Y
1.2 = 1 + 200Y
0.2 =200Y
Y=0.2/200 = 0.001 /°C
option (b) is correct
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