Question

Please solve these questions

Answer 1

We know that days in the month April = 30.
Now, Electricity consumed
a) 4bulbs * 60 W * 6 Hours * 30 day = 43200 WH
b) 3 tubes * 40 W * 8 Hours * 30 day = 28800 WH
c) 4 fans *200W * 10 Hours * 30 day = 24000 WH
Total electricity consumed = (43200 + 28800+24000)WH = 96000 WH = 96 KWH
As we know , 1 unit = 1 KWH.
Total cost = 25 *2.50 + (96-25) *5.00
= Rs 417.50.

Answer 2

Hi friend,

(1) Since the 4 bulbs are conne ted everyone one will have the same power.

:- p=p1+p2+p3+p4

P= 60+60+60+60

P= 240 watts.

Bulb works for 6 hours in kWh is,

Energy for 6 hours = 240×6/1000

Energy for 30 days(April) = 240×6×30/1000

Energy = 43.2 kWh.

Total units consumed above 25 = 43.2-25

=18.2 units.

Cost for first 25 units = 2.50 ×25
Cost = 62.5 rupees

Cost for 18.2 units = 91 rupees.

Total cost = 91+62.5

Total cost = 153.5 rupees.

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This is the solution for 1st sum. Though it goes long I can't do all the three sums.

But it is the procedure for another two sums.just change the number alone.

Hope this helped you a little!!!!