Question

Please solve these questions​

Answer 1

Answer:

i-.

(a²)²+(b²)²+2a²b²

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Answer 2

Step-by-step explanation:

1) Using (a+b)^2 = a2+2ab+b2

we can write,

a4 +2.a2.b2.b4

= a4+2a2b2+b4 (Ans)

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2)Using the same identity as (1)

we can write,

(xy)^2 +2.xy.2z+(2z)^2

= x2y2 +4xyz+4z2 (Answer)

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3) First inside braces we use formula

a2-b2= (a+b)(a-b)

So,we write

{(a+b)(a-b)}^2

=. (a+b)(a-b) (a+b)(a-b)

Rearranging

(a+b)^2 x (a-b)^2

we will use i) (a+b)^2 = a2+2ab+b2

and, ii) (a-b)^2 =a2 -2ab+b2

So,

(a2+2ab+b2) ×(a2-2ab +b2). (Ans)

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4) Using (a-b)^2 = a2-2ab+b2

we can write,

(4x)^2 -2.4x.5+(5)^2

= 16x2 -40x +25 (Ans)

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5) Using the same identity as (4)

we can write,

(7x)^2 -2.7x.4 + (4)^2

=49x2 -56x +16 (Ans)

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6) Use. (a+b)^2 formula to do it

Ans). 16l2 + 40lm+25m2 (Ans)

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