Please solve these questions briefly.
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question 72, 73 ,74 answer is in the attached file.
question no.77
BADC is a cyclic quadrilateral.
angleADC+angleABC=180
angleABC=180-140=40.
angleACB=90(angle in semicircle)
In triangle ACB
angle BAC=180-(90+40
=180-130=50
Remaining question I didn't no.
question no.77
BADC is a cyclic quadrilateral.
angleADC+angleABC=180
angleABC=180-140=40.
angleACB=90(angle in semicircle)
In triangle ACB
angle BAC=180-(90+40
=180-130=50
Remaining question I didn't no.
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kartikeymishra:
intuition 75 Angle B A D =angleDCE= 180 degree(if one side of a cyclic quadrilateral is produced then the exterior angle is equal to the interior opposite angle)
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