Question

please solve these questions I will be very happy​

Answer 1

i).
${ \frac{7}{4} }^{ - 3} \times { \frac{7}{4} }^{ - 5} = { \frac{7}{4} }^{3x - 2}$
${ \frac{7}{4} }^{ - 3 + ( - 5)} = { \frac{7}{4} }^{3x - 2} \\ \\ { \frac{7}{4} }^{ - 8} = { \frac{7}{4} }^{3x - 2}$
Bases are same, therefore
$- 8 = 3x - 2 \\ - 3x = - 2 + 8 \\ - 3x = 6 \\ x = \frac{6}{ - 3} \\ x = - 2$