Math, asked by maangursangat, 7 months ago

Please solve these two questions (i) & (iii) and please don't give wrong answers ,please solve it fast

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Answered by aryan073

Answer:

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Q1) Find the products of ::

(1) m²x3m*18x6m²²

$= {3m}^{20 } \times {m}^{22} = {3m}^{44}$

3) (-20/7)mn6x(14/5m*6n)

the answer will be

-280/35m*6n*

$\frac{ - 280}{35} \times {m}^{7} \times {n}^{7} = \frac{ - 280}{35} {m}^{7} \times {n}^{7}$

OK friend hence proved

Answered by Parshva7474

Answer is

first add m2 + m18 + m22 and

multiply 3 by 6

so the answer will be 18m42

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