Question

please solve thies question​

Answer 1

Answer:

c) 23/3

d) 29/9

e) 23/7

f) 10

Step-by-step explanation:

Hope this helps you mate

Answer 2

Correct Question-:

• Solve the following-:

• A ) $\underline{\sf{\: 3 \dfrac{1}{3}+4\dfrac{1}{3}}}$
• B ) $\underline{\sf{ 2 \dfrac{1}{9}+1\dfrac{1}{9}}}$
• C) $\underline{\sf{ 1 \dfrac{1}{7}+2\dfrac{1}{7}}}$
• D ) $\underline{\sf{ 5 \dfrac{2}{3}+4\dfrac{1}{3}}}$

AnswEr-:

• $\underline{\boxed{\sf{ Answer\:of\;a\:= \dfrac{23}{3}}}}$
• $\underline{\boxed{\sf{ Answer\:of\:b\:= \dfrac{28}{9}}}}$
• $\underline{\boxed{\sf{ Answer\:of\:c= \dfrac{23}{7}}}}$
• $\underline{\boxed{\sf{ Answer\:of\:d\:= \dfrac{10}{1}\:or\:10}}}$

Explanation-:

$\dag{\underline{\sf{\:Solution \:of\:(a) \:\:.}}}$

• $\underline{\sf{Solve\:this\:-: 3 \dfrac{1}{3}+4\dfrac{1}{3}}}$

• $\dag{\sf{\: Now \:.}}$

• $\longrightarrow{\sf{ 3 \dfrac{1}{3}+4\dfrac{1}{3}}}$

• $\star{\sf{\: 3 \dfrac{1}{3} =\: \dfrac{10}{3}\: and \: 4\dfrac{1}{3}\:=\:\dfrac{13}{3} \:.}}$

• $\longrightarrow{\sf{ \dfrac{10}{3}+\dfrac{13}{3}}}$

• $\longrightarrow{\sf{ \dfrac{10+13}{3}}}$

• $\longrightarrow{\sf{ \dfrac{23}{3}}}$

$\dag{\sf{\: Therefore-:\:.}}$

• $\underline{\boxed{\sf{ Answer\:of\;a\:= \dfrac{23}{3}}}}$

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$\dag{\underline{\sf{\:Solution \:of\:(b) \:\:.}}}$

• $\underline{\sf{Solve\:this\:-: 2 \dfrac{1}{9}+1\dfrac{1}{9}}}$

$\dag{\sf{\: Now \:.}}$

• $\longrightarrow{\sf{ 2 \dfrac{1}{9}+1\dfrac{1}{9}}}$

• $\star{\sf{\: 2 \dfrac{1}{9} =\: \dfrac{19}{9}\: and \: 1\dfrac{1}{9}\:=\:\dfrac{10}{9} \:.}}$

• $\longrightarrow{\sf{ \dfrac{19}{9}+\dfrac{10}{9}}}$

• $\longrightarrow{\sf{ \dfrac{19+9}{9}}}$

• $\longrightarrow{\sf{ \dfrac{28}{9}}}$

• $\dag{\sf{\: Therefore-:\:.}}$

$\underline{\boxed{\sf{ Answer\:of\:b\:= \dfrac{28}{9}}}}$

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$\dag{\underline{\sf{\:Solution \:of\:(c) \:\:.}}}$

• $\underline{\sf{Solve\:this\:-: 1 \dfrac{1}{7}+2\dfrac{1}{7}}}$

$\dag{\sf{\: Now \:.}}$

• $\longrightarrow{\sf{ 1 \dfrac{1}{7}+2\dfrac{1}{7}}}$

• $\star{\sf{\: 1 \dfrac{1}{7} =\: \dfrac{8}{7}\: and \: 2\dfrac{1}{7}\:=\:\dfrac{15}{7} \:.}}$

• $\longrightarrow{\sf{ \dfrac{8}{7}+\dfrac{15}{7}}}$

• $\longrightarrow{\sf{ \dfrac{8+15}{7}}}$

• $\longrightarrow{\sf{ \dfrac{23}{7}}}$

$\dag{\sf{\: Therefore-:\:.}}$

• $\underline{\boxed{\sf{ Answer\:of\:c= \dfrac{23}{7}}}}$

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$\dag{\underline{\sf{\:Solution \:of\:(d) \:\:.}}}$

• $\underline{\sf{Solve\:this\:-: 5 \dfrac{2}{3}+4\dfrac{1}{3}}}$

$\dag{\sf{\: Now \:.}}$

• $\longrightarrow{\sf{ 5 \dfrac{2}{3}+4\dfrac{1}{3}}}$

• $\star{\sf{\: 5 \dfrac{2}{3} =\: \dfrac{17}{3}\: and \: 4\dfrac{1}{3}\:=\:\dfrac{13}{3} \:.}}$

• $\longrightarrow{\sf{ \dfrac{17}{3}+\dfrac{13}{3}}}$

• $\longrightarrow{\sf{ \dfrac{17+13}{3}}}$

• $\longrightarrow{\sf{ \dfrac{\cancel{30}}{\cancel{3}}}}$

• $\longrightarrow{\sf{ \dfrac{\cancel{10}}{\cancel{1}} \:or\:10 .}}$

$\dag{\sf{\: Therefore-:\:.}}$

• $\underline{\boxed{\sf{ Answer\:of\:(d)\:= \dfrac{10}{1}\:or\:10}}}$

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$\dag{\sf{\: Hence -:\:.}}$

1. $\underline{\boxed{\sf{ Answer\:of\;a\:= \dfrac{23}{3}}}}$
2. $\underline{\boxed{\sf{ Answer\:of\:b\:= \dfrac{28}{9}}}}$
3. $\underline{\boxed{\sf{ Answer\:of\:c= \dfrac{23}{7}}}}$
4. $\underline{\boxed{\sf{ Answer\:of\:d\:= \dfrac{10}{1}\:or\:10}}}$

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