please solve this 1/x - 1/x-2 =3
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Answer:
1/x and -1/x can be cancelled so
-1-2=3
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Roots of the equation are ( 3 ± √15 ) / 3
Step-by-step explanation:
1/x - 1/(x - 2 ) = 3
=> ( x - 2 - x ) / [ x( x - 2 ) = 3
=> - 2 / ( x² - 2x ) = 3
=> - 2 = 3( x² - 2x)
=> - 2 = 3x² - 6x
=> 3x² - 6x + 2 = 0
Using Quadratic formula
=> x = ( - b ± √D) / 2a
Comaring 3x² - 6x - 2 = 0 with ax² + bx + c = 0 we get
a = 3
b = - 6
c = - 2
D = b² - 4ac = ( - 6 )² - 4(3)(-2) = 36 + 24 = 60
=> x = ( 6 ± √60 ) / 6
=> x = ( 6 ± 2√15 ) / 6
=> x = ( 3 ± √15 ) / 3
Therefore the roots of the equation are ( 3 ± √15 ) / 3
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