Question

please solve this....​

Answer 1

Solution

$= > \frac{3 - \sqrt{5} }{3 + 2 \sqrt{5} } = a \sqrt{5} - b \\ = > \frac{(3 - \sqrt{5})(3 - 2 \sqrt{5} )}{(3 + 2 \sqrt{5} )(3 - 2 \sqrt{5}) } = a \sqrt{5} - b \\ = > \frac{9 - 11\sqrt{5} + 10 }{3 {}^{2} - (2 \sqrt{5}) {}^{2} } = a \sqrt{5} - b \\ = > \frac{19 - 11 \sqrt{5} }{9 - 20} = a \sqrt{5} - b \\ = > - \frac{19}{11} + \frac{11}{11} \sqrt{5} = a \sqrt{5} - b \\ = > (1) \sqrt{5} - \frac{19}{11} = a \sqrt{5} - b \\ = > compairing \: the \: both \: sides \: \: \\ a = 1 \\ b = \frac{19}{11}$