please solve this...
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Step-by-step explanation:
a = 3 - b
a3 + b3 = (3-b)^3 + b3
9 = 27-b3-9b(3-b) + b3
9 = 27-27b+9b2
0 = 18 -27b+9b2
0 = b2-3b+2
0= b2-b-2b+2
0= (b-1) (b-2)
b= 1 or b= 2
a = 1 or a = 2
an = 2
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