Question

please solve this....​

Answer 1

Explanation:

FORMULA FOR TIME PERIOD OF A SIMPLE PENDULUM

IS GIVEN BY

T= $2\pi \times \sqrt{ \</em></strong><strong><em>d</em></strong><strong><em>frac{l}{g} }$

WHERE

T=TIME PERIOD

l=LENGTH OF PENDULUM

g= ACCELERATION DUE TO GRAVITY

IN BOTH CASES THE SAME PENDULUM IS USED SO THE LENGTH REMAINS UNCHANGED

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FOR g1=9.8m/s²

T1 = $2\pi \times \sqrt{ \</em></strong><strong><em>d</em></strong><strong><em>frac{l}{</em></strong><strong><em>g1</em></strong><strong><em>} } </em></strong></p><p></p><p><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em>=</em></strong><strong><em> </em></strong><strong><em> 2\pi \times \sqrt{ \</em></strong><strong><em>d</em></strong><strong><em>frac{l}{</em></strong><strong><em>9</em></strong><strong><em>.</em></strong><strong><em>8</em></strong><strong><em>} }$

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FOR g2=4.36m/s²

T2= $2\pi \times \sqrt{ \</em></strong><strong><em>d</em></strong><strong><em>frac{l}{</em></strong><strong><em>g2</em></strong><strong><em>} }$

= $2\pi \times \sqrt{ \</em></strong><strong><em>d</em></strong><strong><em>frac{l}{</em></strong><strong><em>4</em></strong><strong><em>.</em></strong><strong><em>3</em></strong><strong><em>6</em></strong><strong><em>} }$

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$\</em></strong><strong><em>d</em></strong><strong><em>frac{</em></strong><strong><em>T</em></strong><strong><em>1}{ </em></strong><strong><em>T</em></strong><strong><em>2} = \</em></strong><strong><em>d</em></strong><strong><em>frac{2\pi \times \sqrt{ \</em></strong><strong><em>d</em></strong><strong><em>frac{l}{9.8} } }{2\pi \times \sqrt{ \</em></strong><strong><em>d</em></strong><strong><em>frac{l}{4.36} } }$

$= \sqrt{ \</em></strong><strong><em>d</em></strong><strong><em>frac{4.36}{9.8} }$

= √109:√245

So The Ratio Of Time Periods Is

√109:√245

Answer 2

Answer:

Above one....