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a/b+c +b/c+a +c/a+b =1
multiplying both sides by a+b+c we get (a+b+c not equal to 0)
=a(a+b+c)/b+c +b(a+b+c)/c+a +c(a+b+c)/a+b
=(a+b+c)
=a^2/b+c +a(b+c)/b+c b^2/c+a +b(c+a)/c+a +c^2/a+b +c(a+b)/a+b
=(a+b+c)
=a^2/b +a +b^2/c+a +b +c^2/a+b +c
= (a+b+c)
=a^2/b+c +b^2/c+a +c^2/a+b =0
proved
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multiplying both sides by a+b+c we get (a+b+c not equal to 0)
=a(a+b+c)/b+c +b(a+b+c)/c+a +c(a+b+c)/a+b
=(a+b+c)
=a^2/b+c +a(b+c)/b+c b^2/c+a +b(c+a)/c+a +c^2/a+b +c(a+b)/a+b
=(a+b+c)
=a^2/b +a +b^2/c+a +b +c^2/a+b +c
= (a+b+c)
=a^2/b+c +b^2/c+a +c^2/a+b =0
proved
HOPE THIS ANSWER WILL HELP YOU
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