Please solve this…..
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Answer:
Given:
cos∅cos(90°-∅)/tan(90°-∅)+cos∅sin(90°-∅
Important formulas which you have to follow to calculate this:
- sin(90°-∅)=cos∅ cot∅=1/tan∅
- cos(90°-∅)=sin∅ sin²∅+cos²∅=1
- tan(90°-∅)=cot∅
- cot(90°-∅)=tan∅
Process:
cos∅cos(90°-∅)/tan(90°-∅)+cos∅sin(90°-∅)
=cos∅sin∅/cot∅+cos∅cos∅
=cos∅sin∅×sin∅/cos∅+cos²∅
=sin²∅+cos²∅(cos∅ and cos∅ cancel out)
=1
It is your answer.Hope you understand.
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