Question

please solve this...

Answer 1

♥️Hope u like my process♥️
=========================
$\bf{ionisation \: \: energy} = the \: energy \: \: required \: to \: \: remove \: \: an \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf \: electron \: \: from \: \: 1 \: \: mole \: \: of \: atom.$
So..

1 mole = $\bf \: Avagardo \: \: number \: \: of \: \: atoms\: \:$

Energy required to ionise half mole (½ of Avagardo number of atoms) = $\bf \: \delta\: \: H$

So

Ionization Energy required for 1 mole of the gas X = $\bf 2 \: \: \delta \: \: H$

I.E. of for Avagardo number (Na) of atoms = $\bf 2\: \: \delta \: \: H$

Thus

I.E. of 1 atom of X
$= \bf \frac{2 \: \: ( \delta \: \: H)}{Na}$
_________________________
Hope this is ur required answer

Proud to help you

Answer 2

Answer:

answer = a

Explanation: