please solve this ,anyone?
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hey mate
area of rectangle=16×12 =192 cm²
let diagonal bd
so, right angle traingle bdc
so, use Pythagoras theorem
bd²=dc²+bc²
bd²=(12)²+(16)²
bd²=144 +256=400
bd²=400
Bd = 20 cm
Bd is diameter
d=20cm
so,r=10cm
area of circle is πr²
=3.14×(20)²
=3.14×400
=1,256 cm²
hope it's helpful you
Mark me brainlist ❤️❤️✌️ you
area of rectangle=16×12 =192 cm²
let diagonal bd
so, right angle traingle bdc
so, use Pythagoras theorem
bd²=dc²+bc²
bd²=(12)²+(16)²
bd²=144 +256=400
bd²=400
Bd = 20 cm
Bd is diameter
d=20cm
so,r=10cm
area of circle is πr²
=3.14×(20)²
=3.14×400
=1,256 cm²
hope it's helpful you
Mark me brainlist ❤️❤️✌️ you
anasisin:
thanks ,but how come you know diagnol passes through the centre?
bd is the diagnol i know. but does it pass through the centre
how did you know sir? is it any rule?
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