please solve this arithmetic progression
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let, the terms be (a-d), a, (a+d)
where d is common difference.
now
(a-d) + a + (a+d) =21
hence, a=7
again
(a-d)(a+d)= a+6
a^2-d^2=7+6
7^2-d^2=13
d^2=36
hence d=6..
therefore the numbers are 1,7,13
where d is common difference.
now
(a-d) + a + (a+d) =21
hence, a=7
again
(a-d)(a+d)= a+6
a^2-d^2=7+6
7^2-d^2=13
d^2=36
hence d=6..
therefore the numbers are 1,7,13
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