Math, asked by prem4522, 1 year ago

please solve this equation

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Answered by gangwarakash999
3
Hope it helps you (:)
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Answered by Anonymous
1
\underline{\mathsf{ Solution : }}

\mathsf{ Given, }

 \mathsf{ \implies 7( y \: + \: 3) \: - \: 2(x \: + \: 2) \: = \: 14} \\ \\ \mathsf{ \implies 7y \: + \: 21 \: - \: 2x \: - \: 4 \: = \: 14} \\ \\ \mathsf{ \implies - 2x \: + \: 7y \: + \: 17 \: = \: 14} \\ \\ \mathsf{ \implies - 2x \: + \: 7y \: = \: 14 \: - \: 17} \\ \\ \mathsf{ \implies - 2x \: + \: 7y \: = \: - 3} \\ \\ \mathsf{ \implies \cancel{- }(2x \: - \: 7y ) \: = \: \cancel{ - }3} \\ \\ \mathsf{ \therefore \: \: 2x \: - \: 7y \: = \: 3 \qquad...(1)}

\mathsf{ And, } \\ \\ \mathsf{ \implies 4(y \: + \: 2 \: ) \: + \: 4(x \: + \: 3 \: ) \: = \: 44} \\ \\ \mathsf{ \implies 4y \: + \: 8 \: + \: 4x \: + \: 12 \: = \: 44} \\ \\ \mathsf{ \implies4x \: + \: 4y \: + \: 20 \: = \: 44} \\ \\ \mathsf{ \implies4x \: + \: 4y \: = \: 44 \: - \: 20} \\ \\ \mathsf{ \implies4(x \: + \: y) \: = \: 24} \\ \\ \mathsf{ \implies x \: + \: y \: = \: \dfrac{24}{4} } \\ \\ \mathsf{ \implies x \: + \: y \: = \: 6} \\ \\ \mathsf{ \therefore \: \: x \: = \: 6 \: - \: y \qquad ...(2)}

\mathsf{ Plug \: the \: value \: of \: ( 2 ) \: in \: ( 1 ) : } \\ \\ \mathsf{ \implies2x \: - \: 7y \: = \: 3} \\ \\ \mathsf{ \implies2(6 \: - \: y) \: - \: 7y \: = \: 3} \\ \\ \mathsf{ \implies12 \: - \: 2y \: - \: 7y \: = \: 3} \\ \\ \mathsf{ \implies12 \: - \: 9y \: = \: 3} \\ \\ \mathsf{ \implies12 \: - \: 3 \: = \: 9y} \\ \\ \mathsf{ \implies 9 \: = \: 9y} \\ \\ \mathsf{ \implies y\: = \: \dfrac{9}{9}} \\ \\ \mathsf{ \implies y \: = \: 1 }

\mathsf{ Plug \: the \: value \: of \: y \: in \: ( 1 ) , } \\ \\ \mathsf{ \implies x \: = \: 6 \: - \: y} \\ \\ \mathsf{ \implies x \: = \: 6 \: - \: 1} \\ \\ \mathsf{ \therefore x \: = \: 5} \: \\ \\
 \boxed{ \underline{ \mathsf{ \implies x \: = \: 5 \: \: and \: \: y \: = \: 1 }}}
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