Question

please solve this example​

Answer 1

Given If height of a satellite completing one Revolution around the earth in T seconds is h1 meter, then what would be the height of a satellite taking 2√2T seconds for one Revolution

Given T1 = T, T2 = 2√2 T, r1 = R + h1, r2 = R + h2  

We know that t is directly proportional to cube of major axis.  

  T1^2 / T2^2 = r1^3 / r2^3

   T^2 / (2√2 T)^2 = (R + h1)^3 / (R + h2)^3

   8(R + h1)^3 = (R + h2)^3

  (R + h2)^3 = (2 (R + h1)^3

 R + h2 = 2 R + 2h1

 h2 = 2 R - R + 2h1

h2 = R + 2 h1

Answer 2

Answer:

H2=r+2h1 will be the correct answer hope it helps you