PLEASE SOLVE THIS EXPONENT PROMBLEM
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Answer: We know that,
=(5)
−1
=(1/5)
1
...[∵(a/b)
−n
=(b/a)
n
]
=(7)
−1
=(1/7)
1
...[∵(a/b)
−n
=(b/a)
n
]
Now subtract,
={(1/5)−(1/7)}
−1
={(7−5)/35}
−1
...[LCM of 5 and 7 is 35]
={2/35}
−1
={35/2}
HAVE A NICE DAYYYY
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