please Solve This Fast..........♡......♡..........
Attachments:
Answers
Answered by
1
Since OA = OB ----radii
So Angle OAB = OBA
So Angle AOB = 180-100
= 80°
Hence x = 180-80 -----linear line
x = 100
since x + y = 180
So y = 180-100
y = 80
So Angle OAB = OBA
So Angle AOB = 180-100
= 80°
Hence x = 180-80 -----linear line
x = 100
since x + y = 180
So y = 180-100
y = 80
tisha16:
y is 130 not 80
how ??
Answered by
1
In triangle OAB we have
OA=OB(radius of the circle)
OAB=OBA=50°
AOB=80°
then OBD=x=180°-80°=100°(linear pair)
In cyclic quadilateral ADBC
angle A+angle C=180°
angleC=180°-50°=130°= y
x=100 y= 130
OA=OB(radius of the circle)
OAB=OBA=50°
AOB=80°
then OBD=x=180°-80°=100°(linear pair)
In cyclic quadilateral ADBC
angle A+angle C=180°
angleC=180°-50°=130°= y
x=100 y= 130
Similar questions