please solve this fastly
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(xy)^3 + 1^3
=(xy +1) [(xy)^2 +1 -xy]
=(xy +1) [(xy)^2 +1 -xy]
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Here is your answer ―
Q. x^3y^3 + 1
= (xy + 1) (x^2y^2 - xy + 1)
{tip ― use the Identity a^3 + b^3 = a^2 - ab + b^2}
Hope this helped you
@PoojaBBSR
Q. x^3y^3 + 1
= (xy + 1) (x^2y^2 - xy + 1)
{tip ― use the Identity a^3 + b^3 = a^2 - ab + b^2}
Hope this helped you
@PoojaBBSR
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