please solve this for me
Attachments:
john44:
use Pythagorean triplet 6,8,10 thats it
Answers
Answered by
1
I think you have got the correct answer
Attachments:
if my answer is correct can you mark it as brainliest
doesn't it obvious that ur answee is wrong
of my question
which u answered
Answered by
0
inADB p=8,h=10 ab^2=10^2-6=8^2
ab=6
abc in p=6 b=4 to b=√52
sin thita =p/h=4/√52×√52×√52=√52/13
cos thora =b/h=6/√52×√52/√52=3√52/26
is your answer
plz mark brainlist
ab=6
abc in p=6 b=4 to b=√52
sin thita =p/h=4/√52×√52×√52=√52/13
cos thora =b/h=6/√52×√52/√52=3√52/26
is your answer
plz mark brainlist
Similar questions