Question

please solve this for me

Answer 1

HEY THERE!!!


Question:-



$\frac{3x}{10} + \frac{2x}{5} = \frac{7x}{25} + \frac{29}{25} \\ \\ \\ \frac{3x + 4x}{10} = \frac{7x + 29}{25} \\ \\ 25(3x + 4x) = 10(7x + 29) \\ \\ \\ 25(7x) = 70x + 290 \\ \\ \\ \\ 175x = 70x + 290 \\ \\ 175x - 70x = 290 \\ \\ 105x = 290 \\ \\ \\ x = \frac{290}{105} = \frac{58}{21} \\ \\ x = \frac{58}{21}$

Answer 2

$\underline{\bold{Answer:-}}$

$\\ \\ \frac{3x}{10} + \frac{2x}{5} = \frac{7x}{25} + \frac{29}{25} \\ \\ = > \frac{3x + 4x}{10} = \frac{7x + 29}{25} \\ \\by \: cross \: multiplication \\\\ = > 25(3x + 4x) = 10(7x + 29) \\ \\ = > 75x + 100x = 70x + 290 \\ \\ = > 175x = 70x + 290 \\ \\ = > 175 x - 70x = 290 \\ \\ = > 105x = 290 \\ \\ = > x = \frac{290}{105 } \\ \\ = > x = 58 / 21.$



$\textbf{Hope it helps!}$