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In the given triangle ABC,
∠ ABC = 90°
∠ BAC = ∠ BCA
AB = BC
AC = √8
We know that,
AB = AC
Then for surely,
∠BAC = ∠BCA
[ Angles opposite to the equal sides]
We also know that,
Δ ABC is a right angle triangle.
Then,
∠ABC = 90°
According to the angle sum property of a triangle,
∠ ABC + ∠ BAC + ∠BCA = 180°
90° + ∠ BAC + ∠BCA = 180°
We know that,
∠BAC = ∠BCA
That is,
90° + 2∠BAC = 180°
2∠BAC = 180° - 90°
2∠BAC = 90°
∠BAC = 90°/2
∠BAC = 45°
That is,
∠BAC = ∠BCA = 45°.
We know that sum of the angles of a Δ = 180°
We know,
∠ABC = 90°
∠ABC + ∠BAC + ∠BCA = 180°
On substituting values ,
90° + 45° + 45° = 180°
180° = 180°
LHS = RHS
Hence verified !!
All Done!! ☺
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