the sum of the first 41 terms of an ap is 41. find the 21st term
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let the 1st term is a
common difference=d
then , sum of first 41 terms
41/2{2.a+(41-1).d=41
=> 2a+40d=2
=> 2(a+20d)=2
=> a+20d=2/2=1
=> a+(21-1).d=1
21st term =a+(21-1).d
so,21st term =1
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