Question

please solve this..
guys​

Answer 1

Answer:

320m

Explanation:

$ut + \frac{1}{2} a {t}^{2}$

Since, the car is starting from rest, u = 0

Therefore,

$ut = 0$

S1 = 0 + 1/2×5×64 = 160m

Now,

$v = u + at$

V = 0 + 5×8 = 40m/s

Therefore, S2 = 40 ×(12-8)= 40×4= 160m

Hence total distance = S1 + S2 = 160m +160m = 320m

Answer 2

Answer:

320 meter

Explanation:

for first 8sec:

a=5

so, s=ut+1/2at²

=0+1/2×5×8²

=160

where @fter 8 sec final velocity is

v=u+at

v=0+5×8

=40m/s

for rest of period 4s it travels with uniform speed 40m/s(so acceleration is 0)

s=ut+1/2at²

=40×4+0

=160m

total distance is 320 meter