Math, asked by RPK893, 4 months ago

Please Solve this Help please

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Answered by lahari60

1

Answer:

(6a+7)(a+4)

Step-by-step explanation:

6a²+24ab+7a+28

taking 6a as common in first two terms and 7 as common in 3rd and 4th terms.

6a²+24ab+7a+28

6a(a+4)+7(a+4)

as (a+4) is common in both we can conclude it as

(6a+7)(a+4)

I hope my answer helps you ☺☺

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