Question

PLEASE SOLVE THIS .I WILL MARK AS BRAINLIEST AND I WILL THANKS TO THAT WHO WILL GIVE THE RIGHT AND APPLICABLE ANSWER.PLZ QUICK ANSWER PLEASE .

Answer 1

Ans 3:
2m+2=2m+2
2m-2m=2-2
0= ans

Answer 2

Step-by-step explanation:

1st

Let the angle be x.

Its supplement is 180−x

Its complement is 90−x

So, 180−x=4×(90−x)

Or 180−x=360−4x

⟹ x= 180/3 = 60°

2nd

i) speed =72km/hr= 20m/sec

time taken to pass a pole = 140/20

= 7 sec

ii) length of train = 140m

length of platform = 220 m

total length = 360m

speed = 72km/hr=20m/sec

time taken = 360/20

= 18sec

3rd

(16^2)^m×8^2=(2^2)^m+2

(2^8)^m × 2^6 = 2^2m+4

2^8m+6 = 2^2m+4

8m +6= 2m+4

6m=-2

m=-1/3