Please solve this I will mark you Brainliest
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Answer:
(-6x + 21) should be subtracted.
Step-by-step explanation:
Divide (x^4 + 2x^3 + 2x^2 +4x + 6) by (x^2 + 2x - 3).
The remainder will be (-6x + 21).
Then subtract the remainder (i.e; -6x + 21 ), from the Dividend (i.e; x^4 + 2x^3 + 2x^2 +4x + 6) to get the number which is exactly divisible by the quotient (i.e; x^2 + 2x - 3).
So, (-6x + 21) must be subtracted from (x^4 + 2x^3 + 2x^2 +4x + 6).
Answered by
0
Answer:
2 x ki power 7±6 x ki power 3±6
8 x ki power 10±6
14 x ki power 10
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