Math, asked by SwarnimaAnand, 8 months ago

Please solve this I will mark you Brainliest​

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Answered by shreya210325
1

Answer:

(-6x + 21) should be subtracted.

Step-by-step explanation:

Divide (x^4 + 2x^3 + 2x^2 +4x + 6) by (x^2 + 2x - 3).

The remainder will be (-6x + 21).

Then subtract the remainder (i.e; -6x + 21 ), from the Dividend (i.e; x^4 + 2x^3 + 2x^2 +4x + 6) to get the number which is exactly divisible by the quotient (i.e; x^2 + 2x - 3).

So, (-6x + 21) must be subtracted from (x^4 + 2x^3 + 2x^2 +4x + 6).

Answered by jat61637
0

Answer:

2 x ki power 7±6 x ki power 3±6

8 x ki power 10±6

14 x ki power 10

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