Math, asked by saurav130, 1 year ago

please solve this identities

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Answered by cheguethamizh002

0

Answer:

tan2a=1- e2 i.e. sec2a =2-e2

seca + tan3a coseca = 1/cosa + sin2a/cos3a = 1/cosa + (1-cos2a)/cos3a

= 1/cosa + 1/cos3a – 1/cosa = 1/cos3a = sec3a = (2-e2)3/2

Step-by-step explanation:

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