please solve ... this is from the lesson quadratic equation
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it should be your answer
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3x(2x+1)-2(2x+1)
(3x-2)(2x+1)
The roots are (3x-2)(2x+1)=0
therefore, 3x-2=0 or 2x+1=0
x=2\3;x=-1\2.
(3x-2)(2x+1)
The roots are (3x-2)(2x+1)=0
therefore, 3x-2=0 or 2x+1=0
x=2\3;x=-1\2.
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