Question

please solve this it is urgent ​

Answer 1

Answer:You is asking mathematics question in subject geography.

Explanation:

Answer 2

secΘ = 17/8 

⇒ cosΘ = 8/17 

cos²Θ = 64/289 

⇒ sin²Θ = 1 - cos²Θ = 1 - 64/289 = 225/289 

⇒ tan²Θ = sin²Θ/cos²Θ = 225/64 

3 - 4sin²Θ = 3 - 4*225/289 = -33/289 

4cos²Θ - 3 = 4*64/289 - 3 = -611/289 

⇒ (3 - 4sin²Θ) / (4cos²Θ - 3) = 33/611 

And 

3 - tan²Θ = 3 - 225/64 = -33/64 

1 - 3tan²Θ = 1 - 3*225/64 = -611/64 

⇒ (3 - tan²Θ) / (1 - tan²Θ) = 33/611 

⇒ (3 - 4sin²Θ) / (4cos²Θ - 3) = (3 - tan²Θ) / (1 - 3tan²Θ)