please solve this it's very urgent
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Answer:
= √(1+sin x)/√(1-sin x) × √(1+sin x) /√(1+sin x)
= (1+ sin x )/√(1-sin²x) = (1+ sin x )/cos x
= ( 1/cos x +sin x/cos x ) = ( sec x + tan x ).
ANSWER!
So option b) is correct
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√1-sinx/1+sinx=√1-sinx/1+sinx*1-sinx/1-sinx
√(1-sinx) '2/1-sin'2x=1-sinx/cosx= secx-tanx
answer is secx-tanx
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