Question

please solve this its urgent​

Answer 1

Helo mate here your ans

Now, a3+b3 + c3 = (a+ b + c) (a2 + b2 + c2 – ab – be – ca) + 3abc

[using identity, a3+b3 + c3 – 3 abc = (a + b + c)(a2+b2+c2 –ab–bc-ca)] = 0 + 3abc [∴ a + b + c = 0]

a3+b3 + c3 = 3abc.

Hope this ans help you.. xd..

Answer 2

Answer:

Q6 ) answer= 3abc

Step-by-step explanation:

Now, a3+b3 + c3 = (a+ b + c) (a2 + b2 + c2 – ab – be – ca) + 3abc

[using identity, a3+b3 + c3 – 3 abc = (a + b + c)(a2+b2+c2 –ab–bc-ca)] = 0 + 3abc [∴ a + b + c = 0]

a3+b3 + c3 = 3abc.

Q7) Answer=> p=1

Solve (3x+1 ) (3x-1) = 9x^2 -p

9x^2 - 3x + 3x -1 = 9x^2 - p

9x^2 - 1 = 9x^2 - p

( on comparing both sides )

P=1

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