Question

If ph of saturated solution of ba(oh)2 is 12 the value of ksp is

Answer 1

Answer:

Ksp= 5*10^-7

Explanation:

To find out Ksp we need to know solubility of OH- which we can calculate in this case by using the value of pH.

pH+pOH=14

pOH=14-12 = 2

[OH-]=10^-2

The following equilibrium is established when Barium Hydroxide is Dissolved.

$Ba(OH)_2$⇄$Ba^{2+}+ 2OH^-$

                           s      +      2s

it's the 2s which is equal to 10^-2

so s=5*10^(-3)

The solubility product (Ksp) of  barium Hydroxide is 4s^3

so Putting 10^-2 to 4s^3 we get 5*10^-7

Answer 2

Answer:

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