Math, asked by Raulrd7, 11 months ago

Please solve this. Logarithm

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Answered by Anonymous

1

Answer:

2^(3/log3x) = 1/64
2^(3/log3x) = 2^-6
3/ log3x = -6
-2 log 3x = 0
log 3 x = 0

Therefore x =1

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