Math, asked by harsh1221, 1 year ago

please Solve this math

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Answered by Sameerd
1
angle a=angle a(common angle)
ae=ad(given)
ac=ab(by Euclid axiom when equals are added to equals the sums are equals)
so by S. A. S. congruence rule both the triangles ate congruent

harsh1221: thanks bhai
Sameerd: it's ok
Answered by HarishAS
1
Hey friend, Harish here.
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Here is your answer
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Given that,

AE = AD - (i)

BD = EC -(ii)
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To  prove,

Δ AEB ≡ ΔADC
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Proof,

i) In Δ AEB & ΔADC

  AE = AD  ⇒  1st side

ii) ∠A = ∠A (Both have common angles)  ⇒ Angle

iii)  AE = AD  (given)
 
     EC = DB (given) - (ii)

    Now Add (i) & (ii)

     AE + EC = AD + DB

              AC = AB ⇒ 2nd side

∴ΔAEB ≡ Δ ADC  By SAS congruence.
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Hope my answer is helpful to u. 

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