please Solve this math
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angle a=angle a(common angle)
ae=ad(given)
ac=ab(by Euclid axiom when equals are added to equals the sums are equals)
so by S. A. S. congruence rule both the triangles ate congruent
ae=ad(given)
ac=ab(by Euclid axiom when equals are added to equals the sums are equals)
so by S. A. S. congruence rule both the triangles ate congruent
harsh1221:
thanks bhai
Answered by
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Hey friend, Harish here.
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Here is your answer
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Given that,
AE = AD - (i)
BD = EC -(ii)
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To prove,
Δ AEB ≡ ΔADC
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Proof,
i) In Δ AEB & ΔADC
AE = AD ⇒ 1st side
ii) ∠A = ∠A (Both have common angles) ⇒ Angle
iii) AE = AD (given)
EC = DB (given) - (ii)
Now Add (i) & (ii)
AE + EC = AD + DB
AC = AB ⇒ 2nd side
∴ΔAEB ≡ Δ ADC By SAS congruence.
___________________________________________
Hope my answer is helpful to u.
_ _ _ _ _ _ _ _ _ _ _ _ _ _
Here is your answer
_ _ _ _ _ _ _ _ _ _ _ _ _ _
Given that,
AE = AD - (i)
BD = EC -(ii)
_ _ _ _ _ _ _ _ _ _ _ _ _
To prove,
Δ AEB ≡ ΔADC
_ _ _ _ _ _ _ _ _ _ _ _ _
Proof,
i) In Δ AEB & ΔADC
AE = AD ⇒ 1st side
ii) ∠A = ∠A (Both have common angles) ⇒ Angle
iii) AE = AD (given)
EC = DB (given) - (ii)
Now Add (i) & (ii)
AE + EC = AD + DB
AC = AB ⇒ 2nd side
∴ΔAEB ≡ Δ ADC By SAS congruence.
___________________________________________
Hope my answer is helpful to u.
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