Question

please solve this matter fast

Answer 1

I hope it'll help you

Answer 2

so for rationalising this fraction

$\frac{ \sqrt{3} + 1}{ \sqrt{3} - 1}$

$\frac{ \sqrt{3} + 1}{ \sqrt{3} - 1} × \frac{ \sqrt{3} +1}{ \sqrt{3} + 1}$

$\frac{ 3 + \sqrt{3} + \sqrt{3} + 1}{ \sqrt{3^2} - 1^2}$

$\frac{4 + 2\sqrt{3} }{3 - 1}$

$\frac{4 + 2\sqrt{3} }{2}$

$\frac{2(2 + \sqrt{3}) }{2}$

$\frac{2 + \sqrt{3}}{2}$