Question

Please solve this need this urgently

Answer 1

(2/3 )^3 x (2/3)^5 = 2/3^ n-2
(2/3)^3+5 = 2/3 ^ n-2
2/3 ^ 8= 2/3 ^n-2
now 2/3 are canceled with each other
 8= n-2
8+ 2 =n
n= 10
 

Answer 2

Hello friend
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(2/3)³×(2/3)^5=(2/3)^n-2

a^m × a^n = a^(m+n)

(2/3)³×(2/3)^5=(2/3)^3+5

(2/3)^8=(2/3)^n-2

Equating the powers as the bases are equal

8=n-2

n=8+2

n=10
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-3^n+1 × -3^5 = -3^-4

a^m × a^n = a^(m+n)

-3^(n+1+5) = -3^-4

As the bases are equal we can equate the powers

n+6= -4

n= -4-6 = -10
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7^2n+1 ÷ 49 = 7³

49=7²

7^2n+1 ÷ 7² = 7³

7^2n+1 = 7³ × 7²

a^m × a^n = a^(m+n)

7^2n+1 = 7^5

As the bases are same we can equate the powers

2n+1=5

n=4/2=2

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Hope it helps!