Question

please solve this one
(1 +sin theta + cos theta )whole square = (1 + sin theta ) ( 1 + cos theta )

Answer 1

LHS = ( 1 + sin∅ + cos∅)²

use formula ,
( a + b + c)² = a² + b² + c² + 2( ab + bc + ca)

= 1 + sin²∅ + cos²∅ + 2( sin∅ × 1 + sin∅× cos∅ + cos∅ × 1 )

we know ,
sin²∅ + cos²∅= 1

so,

= 1 + 1 + 2sin∅ + 2cos∅ + 2sin∅.cos∅

= 2 + 2sin∅ + 2cos∅ ( 1 + sin∅)

= 2( 1 + sin∅) + 2cos∅( 1 + sin∅)

= 2( 1 + sin∅) ( 1 + cos∅) = RHS

you took some mistake in your question.
question is ,
proved that
( 1 + sin∅ + cos∅)² = 2( 1 + sin∅ )( 1 + cos∅)

Answer 2

Answer:

Step-by-step explanation: