please solve this one
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∠BOC=40° and ∠OAC=30°
Step-by-step explanation:
Given arc AB=twice arc BC and ∠AOB = 80°. We have to find the ∠BOC and ∠OAC.
Let the arc BC be x and also radius r
As,
∴ Arc AB=2x
⇒
Put this value in above equation, we get
⇒
Hence, ∠BOC=40°
∠AOC=80°+40°=120°
Now, by angle sum property in ΔAOC
∠AOC+∠OAC+∠OCA=180°
⇒ 120°+2∠OAC=180°
⇒ ∠OAC=30°
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