please solve this one
heading::: add the following
chapter name::: Algebraic expressions
Exercise::: 6.B
Class::: 7
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Answers
Answered by
1
Answer:
Answer of (b) = pq/6 and answer of (e) = 7x³
Step-by-step explanation:
For (b):-
1/2 pq + (-1/3)pq
=pq/2 - pq/3
=3pq-2pq/6 ------------(LCM)
=pq/6
For (e):-
x³+(-3x³)+4x³+5x³
=x³-3x³+4x³+5x³
=x³+x³+5x³
=2x³+5x³
=7x³
Answered by
2
Answer:
hey mate, here is your answer
Step-by-step explanation:
Answer:( 1st question answer)
→ 1/6 pq
→ Step-by-step explanation:
→ 1/2 pq +(- 1/3 pq) = (1/2 - 1/3) pq
→ = (3-2)/6 pq
→ = 1/6 pq
or
Answer:( 1 st question answer)
1/6pq
Step-by-step explanation:
→ 1/2pq + (-1/3pq)
→ 1/2pq - 1/3pq
→ Take GCD, make denominators equal and then add 'em up!
→ (3-2)/6pq
→ 1/6pq
( both the answers are correct of first question )
2 question answer is the attachment pls refer and though i will text
2) answer
→ x -2 √ x ³- 3 x² + 4 x - 5
→ x ³ - 2x ²
→ - + sign
→ - x ²+ 4 x
→ - x ² + 2 x
→ sign + -
→ 2x- 5
→ 2x - 4
→ - + ( sign)
→ -1
→ Here quotient is x ² - x + 2
→ Remainder = -1
→ hope you have been understood
→ thank you
→ pls kindly refer the attachment for second question there is too answer
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