please solve this please answer me my question
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Answered by
48
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Answered by
2
Answer:
distance x=(t+5)−1x=(t+5)−1
velocity v=dxdtv=dxdt=−(t+5)−2=−(t+5)−2
acceleration a=dvdta=dvdt=2(t+5)−3=2(t+5)−3
Therefore v3/2=−(t+5)−3v3/2=−(t+5)−3
Therefore a=−2v3/2a=−2v3/2
aαv3/2aαv3/2
Hence a is the correct answer.
Explanation:
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