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Given- PA perpendicular to AB , QB perpendicular to AB, PA=QB.
TO prove: ∆OAP = ∆OBQ.
SOLN:
IN ∆OAP & ∆ OBQ
PA= QB----------(GIVEN)
PAO = QBO ---------( 90° )
POA = BOQ ------- ( vertically opposite Angle)
Therefore ∆ OAP = ∆ OBQ ---- (ASA TEST)
OA = OB --------( C.S.C.T)
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