Question

please solve this problem ​

Answer 1

Answer:

Step-by-step explanation:

Let, number of Rs.50 notes be x and number of Rs.100 notes be y

.And total number of notes = 13

Then, number of Rs.10 notes =13−(x+y)

So, value of x notes of Rs.50=50x

Value of y notes of Rs.100=100y

And value of 13−(x+y) notes of Rs.10=[13−(x+y)]×10

So, total value of these notes = 50x+100y+[13−(x+y)]×10  

And it is given that total value of these notes is Rs.830.

So we have;50x+100y[13(x+y)]×10=830⇒50x+100y+130−10x−10y=830⇒40x+90y=700⇒4x+9y=70

Now, there are two variables and one equation.

So here we use hit and trial method to find the value of x and y

.Also, considering the condition that number of Rs.100 notes is more that Rs.50 notes i.e. y>x

Using hit and trial method, put x=1 we have;4×1+9y=70⇒y=669 which is in fractions and can't take as number of notes.

Now, putting x=2 we have;4×2+9y=70⇒y=629 which is also in fraction.

Putting x=4 we have;4×4+9y=70⇒9y=54⇒y=6

So by putting x=4, we have y=6 which also satisfies the condition y>x.

So, number of Rs.50 notes = 4And number of Rs.100 notes = 6

Then number of Rs.10 notes = 13−(4+6)=3