please solve this problem?
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Ade and edf are linear pair of angles. Their sim must be equal to 180° add both the angles u will get x=10° hence angle edf =30° then u can seeabc & edf are equal verically opposite angles. Hence both the lines are parallel.
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ABC=30°
EDF=40-X °
ADE=13X+20 °
SO,(13X+20)+(40 - X)=180
or,12x+60=180
or,12x=180-60=120
∴x=120/12=10
so,EDF=40-10=30
ADE=13*10+20=150
∴ABC=EDF=30°
That's why BC║DE
EDF=40-X °
ADE=13X+20 °
SO,(13X+20)+(40 - X)=180
or,12x+60=180
or,12x=180-60=120
∴x=120/12=10
so,EDF=40-10=30
ADE=13*10+20=150
∴ABC=EDF=30°
That's why BC║DE
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