Please solve this problem
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Answered by
1
Let x be the number.
Given 3/5th of a number exceed its 2/7 by 44.
3/5 * x = 2/7 *x + 44
3/5x - 2/7x = 44
21x - 10x = 35 * 44
11x = 1540
x = 1540/11
x = 140.
The number is 140.
Hope this helps!
Given 3/5th of a number exceed its 2/7 by 44.
3/5 * x = 2/7 *x + 44
3/5x - 2/7x = 44
21x - 10x = 35 * 44
11x = 1540
x = 1540/11
x = 140.
The number is 140.
Hope this helps!
Answered by
0
Let the no. be x. Then
3x/5 =2x/7 +44,then
3x/5-2x/7=44
21x-10x/35=44
11x/35=44
x=44*35/11
x=140
Hope this will help you(-:
3x/5 =2x/7 +44,then
3x/5-2x/7=44
21x-10x/35=44
11x/35=44
x=44*35/11
x=140
Hope this will help you(-:
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