Question

please solve this problem ​

Answer 1

I hope this will help you as this is step wise solving

Answer 2

Answer:

Given:

$\left(a - \dfrac{1}{a} \right) \left(a + \dfrac{1}{a} \right) \left(a^2 + \dfrac{1}{a^2} \right) \left(a^4 + \dfrac{1}{a^4}\right) =\ ?$

Solution:

$\boxed{\boxed{(a+b)(a-b) = a^2 - b^2}}$

$\implies \left(a - \dfrac{1}{a} \right) \left(a + \dfrac{1}{a} \right) \left(a^2 + \dfrac{1}{a^2} \right) \left(a^4 + \dfrac{1}{a^4}\right)$

$\implies \left(a^2 - \dfrac{1}{a^2}\right) \left(a^2 + \dfrac{1}{a^2} \right) \left( a^4 + \dfrac{1}{a^4}\right)$

$\implies \left( a^4 - \dfrac{1}{a^4} \right) \left( a^4 + \dfrac{1}{a^4}\right)$

$\boxed{\implies{\boxed{\left(x^8 - \dfrac{1}{x^8} \right)}}}$