Question

Please solve this problem....​

Answer 1

Answer:

$x - \frac{1}{x}$

Step-by-step explanation:

Above pic is your solution...

Answer 2

Answer:

its an identity

${x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} )$

So in this identity replace,

$x \: by \: {x}^{ \frac{1}{3} } \\ and \\ y \: by \: {x}^{ \frac{ - 1}{3} }$

We get

$( {x}^{ \frac{1}{3} } - {x}^{ \frac{ - 1}{3} } )( {x}^{ \frac{2}{3} } + {x}^{ \frac{ 1}{3} } {x}^{ \frac{ - 1}{3 }} + {x}^{ \frac{ - 2}{3} } ) = {( {x}^{ \frac{1}{3} }) }^{3} - {( {x}^{ \frac{ - 1}{3} }) }^{3} = x - x = 0$